WAEC Physics Practical Questions 2018 and Answers is Out for Free

2018 WAEC EXAM EXPO / 2018 WAEC QUESTIONS AND ANSWERS / FREE RUNS

*_Phy – Pract – Answers_*

1axi)
– *_Precautions_* –
Take Any Two

i ) I avoided conical oscillation

ii) I avoided drought

iii ) I avoided parallax error in taking reading from the metre rule

iv ) I avoided zero error in taking reading from the stop watch

______________________
______________________

2aix)

*_PRECAUTIONS_*
I) experiment must be carried out in a dark room

II) lens, screen and object must be in line

_________________________
3aix)
– *precautions*-
take any two
i ) I removed key when reading is not taking
ii) I ensured tight connections at the terminals
iii ) I avoided parallax error when taking reading from the ammeter .

2ai)
fo=15cm
2av)
a=60.00cm
b=20.00cm
Hence L=a/b=60.00/20.00
L=3
2avi)
TABULATE
S/N:1,2,3,4,5
b(cm):20.00,25.00,35.00,40.00
a(cm):60.00,37.50,30.00,26.25,24.00
L=a/b:3.00,1.50,1.00,0.75,0.60
2avii)
Slope=Change in L/Change in a
=(3-0.25)/(60-18.6)
=2.75/41.4
=0.006642
2aviii)
S^-1=1/S
=(1/0.0066425cm)
S=15.05
S=15cm
2aix)
PRECAUTIONS
-I ensured that all apparatus are in straight line
-I avoided error due to parallax when reading the metre rule
-I avoided zero error on the metre rule
2bi)
u=10cm
f=15cm
Using 1/v+1/u=1/f
1/f-1/u=1/v
1/v=1/15-1/10
1/v=(2-3)/30
1/v=-1/30
v=-30cm
The characteristics of image formed are:
-It is virtual
-It is enlarged and magnified ie twice or two times as big as the object m=2
2bii)
The concave mirror mounted in its holder is moved to and fro in front of the screen until a sharp image of the cross wire of the ray box is formed on the screen adjacent of the object.The distance between the mirror and the screen was measured as 30cm since the radius of curvature r=2fo then half is distance
2bi)
he characteristics of imaged formed are :
i)It is virtual
ii) It is enlarged or magnified i.e. twice or two times bigger as the object(m=2)

(1a)
TABULATE:
S/N: 1, 2 , 3, 4, 5
L(cm): 90.00, 80.00, 70.00, 60.00, 50.00
T(s): 38.00, 36.00, 34.00, 31.00, 28.00
T = t/20(sqt): 1.90, 1.80, 1.70, 1.55, 1.40
√L(cm^1/2): 9.49, 8.94, 8.37, 7.73, 7.07
(1aix)
Slope(s) = Δvertical/Δhorizontal
=1.90 – 1.55/9.49 – 7.75
= 0.35/1.74
S = 0.201
(1ax)
g = 4π�/S�
= 4 �(3.142)�/(0.201)�
= 977.4cm/s�
(1axi)
(i) I ensured the angle of oscillation is relatively small.
(ii) I ensured that no external force is added to the system of oscillation.
(iii) I ensured the oscillation is perfect

(3a)
TABULATE
S/N:1,2,3,4,5
d(cm):25.00,35.00,50.00,65.00,80.00
I(A):0.80,0.75,0.65,0.60
I^-1(A^-1):1.2500,1.3333,1.4286,1.5385,1.6667

(3aviii)
Slope = 

(3aix)
-I ensure tight connections
-I avoided zero error of the ammeter

(3bii)
-Length of the wire
-temperature
-cross sectional area
-Nature of the material

Be the first to comment

Leave a Reply